2i^2+20/3-2i=0

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Solution for 2i^2+20/3-2i=0 equation: 



2i^2+20/3-2i=0

We multiply all the terms by the denominator


2i^2*3-2i*3+20=0

Wy multiply elements

6i^2-6i+20=0

a = 6; b = -6; c = +20;
Δ = b2-4ac
Δ = -62-4·6·20
Δ = -444
Delta is less than zero, so there is no solution for the equation

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